JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
\(\mathrm{A}_{(\mathrm{g})} \rightleftharpoons \mathrm{B}_{(\mathrm{g})}+\frac{\mathrm{C}}{2}(\mathrm{~g})\) The correct relationship between \(K_P, \alpha\) and equilibrium pressure \(P\) is _______.
- A \(K_P=\frac{\alpha^{1 /_2} P^{1 / 2}}{(2+\alpha)^{1 /_2}}\)
- B \(K_P=\frac{\alpha^{3 /_2} P^{1 / 2}}{(2+\alpha)^{1 / 2}(1-\alpha)}\)
- C \(K_P=\frac{\alpha^{1 /_2} P^{3 / 2}}{(2+\alpha)^{3 /_2}}\)
- D \(K_P=\frac{\alpha^{1 /_2} P^{1 / 2}}{(2+\alpha)^{3 /_2}}\)
Answer & Solution
Correct Answer
(B) \(K_P=\frac{\alpha^{3 /_2} P^{1 / 2}}{(2+\alpha)^{1 / 2}(1-\alpha)}\)
Step-by-step Solution
Detailed explanation
Sol:- \(A_{(g)} \rightleftharpoons B_{(g)}+\frac{C}{2}(g)\) \(t=t_{e q}(1-\alpha) \quad \alpha \quad \frac{\alpha}{2}\)…
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