JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
What quantity (in \(mL\)) of a \(45\%\) acid solution of a mono-protic strong acid must be mixed with a \(20\%\) solution of the same acid to produce \(800\, mL\) of a \(29.875\%\) acid solution?
- A \(320\)
- B \(325\)
- C \(316\)
- D \(330\)
Answer & Solution
Correct Answer
(C) \(316\)
Step-by-step Solution
Detailed explanation
\(\frac{{V \times 45}}{{100}} + \frac{{(800 - V) \times 20}}{{100}} = \frac{{800 \times 29.875}}{{100}}\) \( \Rightarrow \frac{{9V}}{{20}} + 160 - \frac{V}{5} = 239\) \( \Rightarrow V = 136\)
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