JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
Assuming that the degree of hydrolysis is small, the \(pH\) of \(0.1\, M\) solution of sodium acetate \((K_a\, = 1.0\times10^{- 5})\) will be
- A \(5\)
- B \(6\)
- C \(8\)
- D \(9\)
Answer & Solution
Correct Answer
(D) \(9\)
Step-by-step Solution
Detailed explanation
sodium acetate is a salt of strong base and weak acid. \(\,pH = 7 + \frac{1}{2}p{K_a} + \frac{1}{2}\,\log \,c\) where \(p{K_a} = - \log \,{K_a} = - \log \,{10^{ - 5}} = 5\) \(\log \,c = \log \,{10^{ - 1}} = - 1\) \(pH = 7 + \frac{5}{2} - \frac{1}{2} = 9.0\)
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