JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
Two liquids A and B form an ideal solution at temperature T K. At T K, the vapour pressures of pure A and B are 55 and 15 \(kNm^{-2}\) respectively. What is the mole fraction of A in solution of A and B in equilibrium with a vapour in which the mole fraction of A is 0.8 ?
- A 0.5217
- B 0.480
- C 0.663
- D 0.340
Answer & Solution
Correct Answer
(A) 0.5217
Step-by-step Solution
Detailed explanation
\(\frac{Y_{A}}{Y_{B}}=\frac{P_{A}^{0}}{P_{B}^{0}}.\frac{X_{A}}{X_{B}}\) \(\frac{0.8}{0.2}=\frac{55}{15}\times\frac{X_{A}}{X_{B}}\) \(\frac{X_{A}}{X_{B}}=\frac{60}{55}=\frac{12}{11}\) \(X_{A}=\frac{12}{23}=0.5217\)
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