JEE Mains · Chemistry · STD 11 - 8.1. Organic chemistry Nomenclature of organic compounds
In sulphur estimation, \(2.0 \times 10^{-3}\) mol of an organic compound (X) (molar mass \(76\) g mol\(^{-1}\)) gave \(0.4813\) g of barium sulphate (molar mass \(233\) g mol\(^{-1}\)). The percentage of sulphur in the compound (X) is ______ \(\times 10^{-1}\) % (Nearest integer)
- A 431
- B 432
- C 433
- D 435
Answer & Solution
Correct Answer
(D) 435
Step-by-step Solution
Detailed explanation
Mass of the organic compound (X) can be calculated as: \(\text{Mass of X} = \text{Moles} \times \text{Molar mass}\) \(\text{Mass of X} = 2.0 \times 10^{-3} \text{ mol} \times 76 \text{ g mol}^{-1} = 0.152 \text{ g}\) In the Carius method for sulphur estimation, the mass of…
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