JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
\(30.4\,kJ\) of heat is required to melt one mole of sodium chloride and the entropy change at the melting point is \(28.4\,J\,K ^{-1}\,mol ^{-1}\) at \(1\,atm\). The melting point of sodium chloride is \(...........K\) (Nearest Integer)
- A \(1070\)
- B \(1060\)
- C \(1050\)
- D \(1040\)
Answer & Solution
Correct Answer
(A) \(1070\)
Step-by-step Solution
Detailed explanation
\(\Delta S =\frac{\Delta H }{ T _{ mp }}\) \(28.4=\frac{30.4 \times 1000}{ T _{ mp }}\) \(T _{ mp }=1070.422\,K\)
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