JEE Mains · Chemistry · STD 11 - 8.3. Organic chemistry purification and characterization
\(1.4\,kg\) of an organic compound was digested according to Kjeldahl 's method and the ammonia evolved was absorbed in \(60\,mL\) of \(M/10\,\,H_2SO_4\) solution. The excess sulphuric acid required \(20\,mL\) of \(M/10\,\,NaOH\) solution for neutralization. The percentage of nitrogen in the compound is
- A \(10\)
- B \(3\)
- C \(24\)
- D \(5\)
Answer & Solution
Correct Answer
(A) \(10\)
Step-by-step Solution
Detailed explanation
Mili equivalents of \(H_2SO_4\) \( = 60 \times \frac{{M \times 2}}{{10}} = 12\) Mili equivalents of \(NaOH = 20 \times \frac{M}{{10}} = 2\) Mili equivalents of \(N{H_3} = 12 - 2 = 10\) \(\% \,\) of nitrogen…
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