JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
In a photoelectric effect experiment the threshold wavelength of incident light is \(380\, nm\), If the wavelength of the incident light is \(260\,nm\), the maximum kinetic energy of emitted electrons will be: .............. \(eV\) Given \(E\) (in \(eV\)) \( = \frac{{1237}}{{\lambda \left( {in\,nm} \right)}}\)
- A \(15.1\)
- B \(1.5\)
- C \(4.5\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(1.5\)
Step-by-step Solution
Detailed explanation
\(\mathrm{K}_{\max }=\frac{\mathrm{hc}}{\lambda}-\frac{\mathrm{hc}}{\lambda_{0}}\) \(\Rightarrow K_{\max }=h c\left(\frac{\lambda_{0}-\lambda}{\lambda \lambda_{0}}\right)\) \(\Rightarrow \mathrm{K}_{\max }=(1237)\left(\frac{380-260}{380 \times 260}\right)\) \(=1.5 \mathrm{eV}\)
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