JEE Mains · Chemistry · STD 11 -p-Block elements - I
The reaction of \(\mathrm{H}_{3} \mathrm{N}_{3} \mathrm{B}_{3} \mathrm{Cl}_{3}\) \((A)\) with \(\mathrm{LiBH}_{4}\) in tetrahydrofurane gives inorganic benzene \((B)\). Further, the reaction of \((A)\) with \((C)\) leads to \(\mathrm{H}_{3} \mathrm{N}_{3} \mathrm{B}_{3}(\mathrm{Me})_{3}\). than Compounds \((\mathrm{B})\) and \((\mathrm{C})\) respectively, are
- A Boron nitride and \(MeBr\)
- B Borazine and \(MeMgBr\)
- C Borazine and \(MeBr\)
- D Diborane and \(MeMgBr\)
Answer & Solution
Correct Answer
(B) Borazine and \(MeMgBr\)
Step-by-step Solution
Detailed explanation
\(\mathrm{H}_{3} \mathrm{N}_{3} \mathrm{B}_{3} \mathrm{Cl}_{3} (A)+3 \mathrm{LiBH}_{4} \xrightarrow [(T.H.F.)]{\text { In terahydrofurane }} \)\(\mathrm{H}_{3} \mathrm{N}_{3} \mathrm{B}_{3} \mathrm{H}_{3}(B)+3LiCl+3BH_3THF\)…
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