ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Motion in plane
  • JEE Mains 2024
  • Hard
  • Numerical

The maximum height reached by a projectile is \(64 \mathrm{~m}\). If the initial velocity is halved, the new maximum height of the projectile is _______ \(\mathrm{m}\).

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(D) \(16\)

Step-by-step Solution

Detailed explanation

\(\mathrm{H}_{\max }=\frac{\mathrm{u}^2 \sin ^2 \theta}{2 \mathrm{~g}}\)

\(\frac{\mathrm{H}_{1 \max }}{\mathrm{H}_{2 \max }}=\frac{\mathrm{u}_1^2}{\mathrm{u}_2^2}\)

\(\frac{64}{\mathrm{H}_{2 \max }}=\frac{\mathrm{u}^2}{(\mathrm{u} / 2)^2}\)

\(\mathrm{H}_{2 \max }=16 \mathrm{~m}\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app