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JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry

It is noticed that \( Pb^{2+} \) is more stable than \( Pb^{2+} \) but \( Sn^{2+} \) is less stable than \( Sn^{4+} \). Observe the following reactions:
\( PbO_{2} + Pb \rightarrow 2PbO; \Delta_{r}G^{\circ} (1) \)
\( SnO_{2} + Sn \rightarrow 2SnO; \Delta_{r}G^{\circ} (2) \)
Identify the correct set from the following.

  1. A \( \Delta_{r}G^{\circ}(1) > 0; \Delta_{r}G^{\circ}(2) < 0 \)
  2. B \( \Delta_{r}G^{\circ}(1) < 0; \Delta_{r}G^{\circ}(2) < 0 \)
  3. C \( \Delta_{r}G^{\circ}(1) < 0; \Delta_{r}G^{\circ}(2) > 0 \)
  4. D \( \Delta_{r}G^{\circ}(1) > 0; \Delta_{r}G^{\circ}(2) > 0 \)
Verified Solution

Answer & Solution

Correct Answer

(C) \( \Delta_{r}G^{\circ}(1) < 0; \Delta_{r}G^{\circ}(2) > 0 \)

Step-by-step Solution

Detailed explanation

\( PbO_{2} + Pb \rightarrow 2PbO \) \( Pb^{2+} \) is more stable hence reaction will be spontaneous. So \( \Delta G^{\circ}_{r}(1) \) is negative. \( SnO_{2} + Sn \rightarrow 2SnO \) \( Sn^{2+} \) is less stable, so reaction will be non-spontaneous hence…