JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
It is noticed that \( Pb^{2+} \) is more stable than \( Pb^{2+} \) but \( Sn^{2+} \) is less stable than \( Sn^{4+} \). Observe the following reactions:
\( PbO_{2} + Pb \rightarrow 2PbO; \Delta_{r}G^{\circ} (1) \)
\( SnO_{2} + Sn \rightarrow 2SnO; \Delta_{r}G^{\circ} (2) \)
Identify the correct set from the following.
- A \( \Delta_{r}G^{\circ}(1) > 0; \Delta_{r}G^{\circ}(2) < 0 \)
- B \( \Delta_{r}G^{\circ}(1) < 0; \Delta_{r}G^{\circ}(2) < 0 \)
- C \( \Delta_{r}G^{\circ}(1) < 0; \Delta_{r}G^{\circ}(2) > 0 \)
- D \( \Delta_{r}G^{\circ}(1) > 0; \Delta_{r}G^{\circ}(2) > 0 \)
Answer & Solution
Correct Answer
(C) \( \Delta_{r}G^{\circ}(1) < 0; \Delta_{r}G^{\circ}(2) > 0 \)
Step-by-step Solution
Detailed explanation
\( PbO_{2} + Pb \rightarrow 2PbO \) \( Pb^{2+} \) is more stable hence reaction will be spontaneous. So \( \Delta G^{\circ}_{r}(1) \) is negative. \( SnO_{2} + Sn \rightarrow 2SnO \) \( Sn^{2+} \) is less stable, so reaction will be non-spontaneous hence…
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