JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
An electrochemical cell, consist of the following two redox couples, \(M^{x+}(aq)/M(s)\) \([E_{red}^\ominus=+0.15\text{ V}]\) and \(Fe^{3+}(aq)/Fe(s)\) \([E_{red}^\ominus=-0.036\text{ V}]\). The cell EMF \((E_{cell})\) is recorded to be \(0.2057\) V. If the reaction quotient of the electrochemical reaction is found to be \(10^{-2}\), then the value of \(x\) is ______. (Nearest integer)
[Given: M is a p-block metal and \(\dfrac{2.303RT}{F}=0.059\) V]
- A 0
- B 1
- C 2
- D 4
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
Given standard reduction potentials: \(E^{\ominus}_{M^{x+}/M} = +0.15\) V \(E^{\ominus}_{Fe^{3+}/Fe} = -0.036\) V Since \(E^{\ominus}_{M^{x+}/M} > E^{\ominus}_{Fe^{3+}/Fe}\), reduction occurs at the \(M^{x+}/M\) electrode (cathode) and oxidation occurs at the \(Fe^{3+}/Fe\)…
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