JEE Mains · Chemistry · STD 12 - 9. Amines
Reaction of ammonia with excess \(Cl _{2}\) gives :
- A \(NH _{4} Cl\) and \(N _{2}\)
- B \(NCl _{3}\) and \(NH _{4} Cl\)
- C \(NH _{4} Cl\) and \(HCl\)
- D \(NCl _{3}\) and \(HCl\)
Answer & Solution
Correct Answer
(D) \(NCl _{3}\) and \(HCl\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{*{20}{c}} {N{H_3} + 3C{l_2} \to NC{l_3} + 3HCl} \\ {excess\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}\)
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