JEE Mains · Physics · STD 11 - 7. gravitation
The maximum and minimum distances of a comet from the Sun are \(1.6 \times 10^{12}\, m\) and \(8.0 \times 10^{10}\, m\) respectively. If the speed of the comet at the nearest point is \(6 \times 10^{4}\, ms ^{-1},\) the speed at the farthest point is ......... \(\times 10^{3}\, m / s\)
- A \(1.5\)
- B \(6.0\)
- C \(3.0\)
- D \(4.5\)
Answer & Solution
Correct Answer
(C) \(3.0\)
Step-by-step Solution
Detailed explanation
By angular momentum conservation \(mv _{1} r _{1}= mv _{2} r _{2}\) \(v _{1}=\frac{48 \times 10^{14}}{1.6 \times 10^{12}}=3000 m / sec\) \(=3 \times 10^{3} m / sec\)
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