Given below are two statements : Statement \(I\) : When speed of liquid is zero everywhere, pressure difference at any two points depends on equation \(\mathrm{P}_1-\mathrm{P}_2=\rho \mathrm{g}\left(\mathrm{h}_2-\mathrm{h}_1\right)\) Statement \(II\) : In ventury tube shown \(2 \mathrm{gh}=v_1^2-v_2^2\) In the light of the above statements, choose the most appropriate answer from the options given below.

\(\mathrm{P}_1+\rho \mathrm{gh}_1+\frac{1}{2} \rho v_1^2=\mathrm{P}_2+\rho \mathrm{gh}_2+\frac{1}{2} \rho v_2^2\)

\(\left[h_1 \& h_2\right.\) are height of point from any reference level]

\(\text { Given } \mathrm{V}_1=\mathrm{V}_2=0 \text { (for statement-1) }\)

\(\therefore \mathrm{P}_1-\mathrm{P}_2=\rho \mathrm{g}\left(\mathrm{h}_2-\mathrm{h}_2\right)\)

For statement-2

\(\mathrm{P}_1+\frac{1}{2} \rho v_1^2=\mathrm{P}_2+\frac{1}{2} \rho v_2^2\)

\(\mathrm{P}_1-\mathrm{P}_2=\rho \mathrm{gh}\)

\(\mathrm{P}_1-\mathrm{P}_2=\frac{1}{2} \rho v_2^2-\frac{1}{2} \rho v_1^2\)

\(\rho \mathrm{gh}=\frac{1}{2} \rho v_2^2-\frac{1}{2} \rho v_1^2\)

\(2 \mathrm{gh}=\mathrm{v}_2^2-\mathrm{v}_1^2\)

Hence answer \((4)\)