JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The ratio of mass percentage (w/w) of C : H in a hydrocarbon is \(12 : 1\). It has two carbon atoms. The weight (in g) of \(CO_2(g)\) formed when \(3.38\) g of this hydrocarbon is completely burnt in oxygen is : (Given : Molar mass in g mol\(^{-1}\) C : 12, H : 1, O : 16)
- A \(5.68\)
- B \(11.44\)
- C \(22.74\)
- D \(17.05\)
Answer & Solution
Correct Answer
(B) \(11.44\)
Step-by-step Solution
Detailed explanation
Ratio of mass percentage of C : H = \(12 : 1\) Ratio of moles of C : H = \(\dfrac{12}{12} : \dfrac{1}{1} = 1 : 1\) The empirical formula is \(CH\). Since the hydrocarbon has two carbon atoms, its molecular formula is \(C_2H_2\). Molar mass of…
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