JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
The group of molecules having identical shape is
- A \(PCl_5,\,IF_5,\, XeO_2F_2\)
- B \(BF_3,\,PCl_3,\,XeO_3\)
- C \(SF_4,\,XeF_4,\,CCl_4\)
- D \(ClF_3,\, XeOF_2,\, XeF_3^+\)
Answer & Solution
Correct Answer
(D) \(ClF_3,\, XeOF_2,\, XeF_3^+\)
Step-by-step Solution
Detailed explanation
\(Cl{I_3} \to \) Hybridisation \( = 3 + \frac{1}{2}[7 - 3] = 5\,(s{p^3}d)\) \(XeOF_2 \to \) Hybridisation \( = 3 + \frac{1}{2}[8 - 4] = 5\,(s{p^3}d)\) \(XeF_3^+ \to \) Hybridisation \( = 3 + \frac{1}{2}[8 - 3 - 1] = 5\,(s{p^3}d)\) All molecules have \(sp^3d\) hybridization and…
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