JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
The number of molecules with energy greater than the threshold energy for a reaction increases five fold by a rise of temperature from \(27^{\circ}\, C\) to \(42^{\circ}\, C .\) Its energy of activation in \(J / mol\) is.............. (Take in \(\ln 5=1.6094;\left.R =8.314\, J mol ^{-1} K ^{-1}\right)\)
- A \(84297.5\)
- B \(84280\)
- C \(84294.7\)
- D \(84285.6\)
Answer & Solution
Correct Answer
(A) \(84297.5\)
Step-by-step Solution
Detailed explanation
\(T _{1}=300 K \quad T _{2}=315 K\) As per question \(K _{ T _{2}}=5 K _{ T _{1}}\) as molecules activated are increased five times so k will increases \(5\) times Now…
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