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JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance

A \(600\,pF\) capacitor is charged by \(200\,V\) supply. It is then disconnected from the supply and is connected to another uncharged \(600\,pF\) capacitor. Electrostatic energy lost in the process is \(.........\,\mu J\).

  1. A \(6\)
  2. B \(5\)
  3. C \(4\)
  4. D \(3\)
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Answer & Solution

Correct Answer

(A) \(6\)

Step-by-step Solution

Detailed explanation

\(Q = CV =600 \times 10^{-12} \times 200=12 \times 10^{-8} C\) \(\text { Initial energy }=\frac{1}{2} CV ^2\) \(=\frac{1}{2} \times 600 \times 10^{-12} \times(200)^2=12\,\mu J\) When connected to another uncharged capacitor Charge will be equally distributed on identical…
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