JEE Mains · Chemistry · STD 11 - 7. Redox reactions
In acidic medium, \(\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7\) shows oxidising action as represented in the half reaction. \(\mathrm{Cr}_2 \mathrm{O}_7^{2-}+\mathrm{XH}^{+}+\mathrm{Ye}^{-} \rightarrow 2 \mathrm{~A}+\mathrm{ZH}_2 \mathrm{O}\) \(\mathrm{X}, \mathrm{Y}, \mathrm{Z}\) and \(\mathrm{A}\) are respectively are _______.
- A \(8, 6, 4\) and \(\mathrm{Cr}_2 \mathrm{O}_3\)
- B \(14,7,6\) and \(\mathrm{Cr}^{3+}\)
- C \(8,4,6\) and \(\mathrm{Cr}_2 \mathrm{O}_3\)
- D \(14,6,7\) and \(\mathrm{Cr}^{3+}\)
Answer & Solution
Correct Answer
(D) \(14,6,7\) and \(\mathrm{Cr}^{3+}\)
Step-by-step Solution
Detailed explanation
The balanced reaction is, \(\mathrm{Cr}_2 \mathrm{O}_7^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_2 \mathrm{O}\) \(\mathrm{X}=14\), \(\mathrm{Y}=6\), \(\mathrm{~Z}=7\), \(\mathrm{A}=\mathrm{Cr}^{3+}\)
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