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JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry

\(500\, g\) of water and \(100\, g\) of ice at \(0\,^oC\) are in a calorimeter whose water equivalent is \(40\, g\). \(10\, g\) of steam at \(100\,^oC\) is added to it. Then water in the calorimeter is ....... \(g\) (Latent heat of ice \(\,= 80\, cal/g\), Latent heat of steam \(\,= 540\, cal/ g\))

  1. A \(580\)
  2. B \(590\)
  3. C \(600\)
  4. D \(610\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(590\)

Step-by-step Solution

Detailed explanation

As \(1\, g\) of steam at \(100\,^oC\) melts \(8\,g\) of ice at \(0\,^oC\). \(10\, g\) of steam will melt \(8\times10\, g\) of ice at \(0\,^oC\) Water in calorimeter \(\,= 500 + 80 + 10\,g\, = 590\,g\)
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