JEE Mains · Chemistry · STD 12 - 7. Alcohol, phenol and ethers
The increasing order of the boiling points for the following compounds is \(\mathop {{C_2}{H_5}OH}\limits_{\left( I \right)} \) \(\mathop {{C_2}{H_5}Cl}\limits_{\left( {II} \right)} \) \(\mathop {{C_2}{H_5}C{H_3}}\limits_{\left( {III} \right)} \) \(\mathop {{C_2}{H_5}OC{H_3}}\limits_{\left( {IV} \right)} \)
- A \((IIl) < (IV) <(II) <(I)\)
- B \((IV) < (III) < (I) < (II)\)
- C \((II) < (III) < (IV) < (I)\)
- D \((III) < (II) < (I) < (IV)\)
Answer & Solution
Correct Answer
(A) \((IIl) < (IV) <(II) <(I)\)
Step-by-step Solution
Detailed explanation
\((I)\) \(C_2H_5OH\) Hydrogen bonding Hydrogen bonding \(>\) Dipole -Dipole \((II)\) \(C_2H_5Cl\) Dipole-Dipole \(C_2H_5Cl\) is more polar than \(C_2H_5OCH_3\) so, Dipole-Dipole \(C_2H_5Cl\) \(>\) Dipole-Dipole \(C_2H_5OCH_3\) \((III)\) \(C_2H_5CH_3\) No hydrogen bonding and…
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