JEE Mains · Physics · STD 12 - 3. current electricity
A wheatstone bridge is initially at room temperature and all arms of the bridge have same value of resistances ( \(R_1=R_2=R_3=R_4\) ). When \(R_3\) resistance is heated to some temperature, its resistance value has gone up by \(10 \%\). The potential difference \(\left( V _{ a }- V _{ b }\right)\) (after \(R _3\) is heated) is ___________ V.

- A 1.05
- B 0
- C 0.95
- D 2
Answer & Solution
Correct Answer
(C) 0.95
Step-by-step Solution
Detailed explanation
\(V_{A}=\frac{V}{2}\) \(V_{B}=\frac{V}{2.1R}\times R=\frac{V}{2.1}\) \(\therefore V _{ A }-V_{B}=V[\frac{1}{2}-\frac{1}{2.1}]\) \(V_{A}-V_{B}=\frac{0.1}{2\times2.1}\times40\) \(V_{A}-V_{B}=\frac{4}{4.2}=0.95\)
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