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JEE Mains · Chemistry · STD 12 - 7. Alcohol, phenol and ethers
The total number of optically active compounds formed in the following reaction is \([Figure]\) \(\xrightarrow{{HBr}}\)
- A \(0\)
- B \(6\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(4\)
Step-by-step Solution
Detailed explanation
The total number of optically active compounds formed is four. The product has two chiral \(C\) atoms. Thus, it has \(2^n\, = 2^2\, = 4\) stereoisomers
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