JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2019
- Medium
- Numerical
The least count of the main scale of a screw gauge is \(1\, mm\). The minimum number of divisions on its circular scale required to measure \(5\,\mu m\) diameter of a wire is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(200\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l}
Least\,count = \frac{{Pitch}}{{No.of\,divisions\,on\,circular\,scale}}\\
5 \times {10^{ - 6}} = \frac{{{{10}^{ - 3}}}}{N}\\
N = 200
\end{array}\)
Least\,count = \frac{{Pitch}}{{No.of\,divisions\,on\,circular\,scale}}\\
5 \times {10^{ - 6}} = \frac{{{{10}^{ - 3}}}}{N}\\
N = 200
\end{array}\)
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