JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
The gas phase reaction \(2NO_2(g) \rightleftharpoons N_2O_4 (g)\) is an exothermic reaction. The decomposition of \(N_2O_4,\) in equilibrium mixutre of \(NO_2(g)\) and \(N_2O_4(g),\) can be increased by
- A addition of an inert gas at constant pressure
- B lowering the temperature
- C increasing the pressure
- D addition of an inert gas at constant volume
Answer & Solution
Correct Answer
(A) addition of an inert gas at constant pressure
Step-by-step Solution
Detailed explanation
Reaction at equilibirium \({N_2}{O_4}\, \rightleftharpoons \,2N{O_2}\) According to Le chatelier's principle- \((a)\) addition of an inert gas at constant pressure will increase volume and equilibirium shifts towards more number of molecules. \((b)\) Decomposition of \(N_2O_4\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- For a metal ion, the calculated magnetic moment is \(4.90\,BM\). This metal ion has \(........\) number of unpaired electons.JEE Mains 2023 Medium
- For a first order reaction \(A \rightarrow B\), the rate constant, \(k =5.5 \times 10^{-14} \,s ^{-1}\). The time required for \(67\, \%\) completion of reaction is \(x \,\times 10^{-1}\) times the half life of reaction. The value of \(x\) is \(....\) (Nearest integer)JEE Mains 2022 Medium
- The standard entropy change for the reaction \(4 Fe ( s )+3 O _{2}( g ) \rightarrow 2 Fe _{2} O _{3}( s )\) is \(-550\, JK ^{-1}\) at \(298 \,K\). [Given : The standard enthalpy change for the reaction is \(-165\, kJ\, mol ^{-1}\). The temperature in \(K\) at which the reaction attains equilibrium is ... . (Nearest Integer)JEE Mains 2022 Medium
- The gas evolved on heating \(CH_3MgBr\) in methanol isJEE Mains 2016 Hard
- 20 mL of 2 M NaOH solution is added to 400 mL of 0.5 M NaOH solution. The final concentration of the solution is _______ \(\times 10^{-2} \mathrm{M}\). (Nearest integer)JEE Mains 2025 Medium
- \(2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{SO}_{3}(\mathrm{~g})\) The above reaction is carried out in a vessel starting with partial pressure \(\mathrm{P}_{\mathrm{SO}_{2}}=250\, \mathrm{~m}\) \(bar,\) \(\mathrm{P}_{0_{2}}=750 \,\mathrm{~m}\) \(bar\) and \(\mathrm{P}_{\mathrm{SO}_{3}}=0 \,\mathrm{bar}\). When the reaction is complete, the total pressure in the reaction vessel is \(.....\mathrm{m}\) \(bar.\) (Round off to the Nearest Integer).JEE Mains 2021 Medium
More PYQs from JEE Mains
- If the two lines \(l_{1}: \frac{ x -2}{3}=\frac{ y +1}{-2}, z =2\) and \(l_{2}: \frac{x-1}{1}=\frac{2 y+3}{\alpha}=\frac{z+5}{2}\) perpendicular, then an angle between the lines \(l_{2}\) and \(l_{3}: \frac{1- x }{3}=\frac{2 y -1}{-4}=\frac{ z }{4}\) isJEE Mains 2022 Medium
- In the given circuit the cells have zero internal resistance. The currents (in Amperes) passing through resistance \(R_1\) and \(R_2\) respectively, are
JEE Mains 2019 Medium - The output of the given circuit diagram is _______.
JEE Mains 2024 Hard - Molality of an aqueous solution of urea is \(4.44 \mathrm{~m}\). Mole fraction of urea in solution is \(x \times 10^{-3}\). Value of \(x\) is _______. (integer answer)JEE Mains 2024 Medium
- A slab of dielectric constant \(K\) has the same crosssectional area as the plates of a parallel plate capacitor and thickness \(\frac{3}{4}\,d\), where \(d\) is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be.(Given \(C _{0}=\) capacitance of capacitor with air as medium between plates.)JEE Mains 2022 Hard
- The common positive oxidation states for an element with atomic number \(24,\) are :JEE Mains 2021 Easy