JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
The amount of electricity in Coulomb required for the oxidation of \(1 \mathrm{~mol}\) of \(\mathrm{H}_2 \mathrm{O}\) to \(\mathrm{O}_2\) is _______ \(\times 10^5 \mathrm{C}\).
- A \(5\)
- B \(8\)
- C \(7\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(2 \mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{O}_2+4 \mathrm{H}^{+}+4 \mathrm{e}^{-}\) \(\frac{\mathrm{W}}{\mathrm{E}}=\frac{\mathrm{Q}}{96500}\) \(\text { mole } \times \text { n-factor }=\frac{\mathrm{Q}}{96500}\) \(1 \times 2=\frac{\mathrm{Q}}{96500}\)…
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