JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
Reduction potential of ions are given below:
| \(ClO_4^{-}\) | \(IO_4^{-}\) | \(BrO_4^{-}\) |
| \(E^{\circ}=1.19 V\) | \(E^{\circ}=1.65 V\) | \(E^{\circ}=1.74 V\) |
- A \(\mathrm{ClO}_4^{-}>\mathrm{IO}_4^{-}>\mathrm{BrO}_4^{-}\)
- B \(\mathrm{BrO}_4^{-}>\mathrm{IO}_4^{-}>\mathrm{ClO}_4^{-}\)
- C \(\mathrm{BrO}_4^{-}>\mathrm{ClO}_4^{-}>\mathrm{IO}_4^{-}\)
- D \(\mathrm{IO}_4^{-}>\mathrm{BrO}_4^{-}>\mathrm{ClO}_4^{-}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{BrO}_4^{-}>\mathrm{IO}_4^{-}>\mathrm{ClO}_4^{-}\)
Step-by-step Solution
Detailed explanation
Higher the value of \(\oplus\) ve \(SRP\) (Std. reduction potential) more is tendency to undergo reduction, so better is oxidising power of reactant. \(Hence, ox. Power:- \mathrm{BrO}_4^{-}>\mathrm{IO}_4^{-}>\mathrm{ClO}_4^{-}\)
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