JEE Mains · Physics · STD 12 - 5. Magnetism and matter
Two magnetic dipoles \(X\) and \(Y\) are placed at a separation \(d\), with their axes perpendicular to each other. The dipole moment of \(Y\) is twice that of \(X\). A particle of charge \(q\) is passing through their mid-point \(P\), at angle \(\theta = 45^o\) with the horizontal line as shown in the figure. What would be the magnitude of force on the particle at that instant ? (\(d\) is much larger than the dimensions of the dipole)

- A \(\left( {\frac{{{\mu _0}}}{{4\pi }}} \right)\frac{M}{{{{\left( {d/2} \right)}^3}}} \times {q^\upsilon }\)
- B \(0\)
- C \(\left( {\frac{{{\mu _0}}}{{4\pi }}} \right)\frac{2M}{{{{\left( {d/2} \right)}^3}}} \times {q^\upsilon }\)
- D \(\sqrt 2 \left( {\frac{{{\mu _0}}}{{4\pi }}} \right)\frac{M}{{{{\left( {d/2} \right)}^3}}} \times {q^\upsilon }\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
\(B_{1}=2\left(\frac{\mu_{0}}{4 \pi}\right) \frac{M}{(d / 2)^{3}} ; B_{2}=\left(\frac{\mu_{0}}{4 \pi}\right) \frac{2 M}{(d / 2)^{3}}\) \(B_{1}=B_{2}\) \(\Rightarrow \) \(B_{net}\) is at \(45^{\circ}\left(\theta=45^{\circ}\right)\) Velocity of charge and \(B_{net}\) are parallel…
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