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JEE Mains · Physics · STD 12 -6. Electromagnetic induction

An ideal capacitor of capacitance \(0.2\, μF\) is charged to a potential difference of \(10\,V\). The charging battery is then disconnected. The capacitor is then connected to an ideal inductor of self inductance \(0.5\,mH\). The current at a time when the potential difference across the capacitor is \(5\,V\), is.....\(A\)

  1. A \(0.17\)
  2. B \(0.15\)
  3. C \(0.34\)
  4. D \(0.25\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.17\)

Step-by-step Solution

Detailed explanation

Given: Capacitance, \(C=0.2\, \mu \mathrm{F}=0.2 \times 10^{-6}\,F\) Inductance \(\mathrm{L}=0.5\, \mathrm{mH}=0.5 \times 10^{-3}\, \mathrm{H}\) Current \(I=?\) Using energy conservation \(\frac{1}{2} C V^{2}=\frac{1}{2} C V_{1}^{2}+\frac{1}{2} L I^{2}\)…
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