JEE Mains · Chemistry · STD 11 - 3. Classification of elements and periodicity in properties
The \(71^{st}\) electron of an element \(X\) with an atomic number of \(71\) enters into the orbital:
- A \(6p\)
- B \(4f\)
- C \(5d\)
- D \(6s\)
Answer & Solution
Correct Answer
(C) \(5d\)
Step-by-step Solution
Detailed explanation
The electron configuration is \([Xe]4f^{14}\,5d^1\,6s^2\)
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