JEE Mains · Chemistry · STD 12 - p -Block elements - ll
On heating, lead\((II)\) nitrate gives a brown gas \((A).\) The gas \((A)\) on cooling changes to a colourless solid/liquid \((B).\) \((B)\) on heating with \(NO\) changes to a blue solid \((C).\) The oxidation number of nitrogen in solid \((C)\) is :
- A \(+5\)
- B \(+2\)
- C \(+4\)
- D \(+3\)
Answer & Solution
Correct Answer
(D) \(+3\)
Step-by-step Solution
Detailed explanation
\(Pb \left( NO _{3}\right)_{2} \stackrel{\Delta}{\longrightarrow} PbO +\underset{ Brown\, gas (A) }{2 NO _{2}}+\frac{1}{2} O _{2}( g )\) \(NO _{2}( g )\)\(\xrightarrow \Delta\) \(\begin{array}{*{20}{c}} {{N_2}{O_3}} \\ {\left( B \right)} \end{array}\)…
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