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JEE Mains · Physics · STD 11 - Newtons laws of motion
  • JEE Mains 2023
  • Medium
  • Numerical

An average force of \(125\,N\) is applied on a machine gun firing bullets each of mass \(10\,g\) at the speed of \(250\,m / s\) to keep it in position. The number of bullets fired per second by the machine gun is:

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Answer & Solution

Correct Answer

(B) \(50\)

Step-by-step Solution

Detailed explanation

\(F = n mv\)

where \(n =\) number of bullets fired per second

\(n =\frac{ f }{ mv }=\frac{125}{10 \times 10^{-3} \times 250}=50\)

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