JEE Mains · Physics · STD 11 - Newtons laws of motion
- JEE Mains 2023
- Medium
- Numerical
An average force of \(125\,N\) is applied on a machine gun firing bullets each of mass \(10\,g\) at the speed of \(250\,m / s\) to keep it in position. The number of bullets fired per second by the machine gun is:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(50\)
Step-by-step Solution
Detailed explanation
\(F = n mv\)
where \(n =\) number of bullets fired per second
\(n =\frac{ f }{ mv }=\frac{125}{10 \times 10^{-3} \times 250}=50\)
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