JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2020
- Medium
- Numerical
A point object in air is in front of the curved surface of a plano-convex lens. The radius of curvature of the curved surface is \(30 \;\mathrm{cm}\) and the refractive index of the lens material is \(1.5 .\) then the focal length of the lens (in \(\mathrm{cm}\) ) is
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Answer & Solution
Correct Answer
(C) \(60\)
Step-by-step Solution
Detailed explanation
Using Lens-Maker's formula
\(\frac{1}{f}=(\mu-1)\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right)\)
\(\Rightarrow \frac{1}{f}=(1.5-1)\left(\frac{1}{30}-0\right)\)
\(\mathrm{f}=60 \mathrm{cm}\)
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