JEE Mains · Physics · STD 11 - 14. waves and sound
The speed of a transverse wave passing through a string of length \(50 \;cm\) and mass \(10\,g\) is \(60\,ms ^{-1}\). The area of cross-section of the wire is \(2.0\,mm ^{2}\) and its Young's modulus is \(1.2 \times 10^{11}\,Nm ^{-2}\). The extension of the wire over its natural length due to its tension will be \(x \times 10^{-5}\; m\). The value of \(x\) is \(...\)
- A \(10\)
- B \(15\)
- C \(13\)
- D \(14\)
Answer & Solution
Correct Answer
(B) \(15\)
Step-by-step Solution
Detailed explanation
\(V _{ T }=\sqrt{\frac{ T }{\mu}}\) \(60=\sqrt{\frac{ T }{10 \times 10^{-3}} \times 0.5}\) \(T =\frac{(60)^{2} \times 10^{-2}}{0.5}=72\,N\) \(\Delta \ell=\frac{ F \ell}{ AY }=\frac{72 \times 0.5}{2 \times 10^{-6} \times 1.2 \times 10^{11}}\)…
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