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JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)

Observe the following equilibrium in a 1 L flask.
\(A(g) \rightleftharpoons B(g)\)
At T(K), the equilibrium concentrations of A and B are 0.5 M and 0.375 M respectively. 0.1 moles of A is added into the flask and heated to T(K) to establish the equilibrium again. The new equilibrium concentrations (in M) of A and B are respectively.

  1. A 0.367, 0.275
  2. B 0.53, 0.4
  3. C 0.742, 0.557
  4. D 0.557, 0.418
Verified Solution

Answer & Solution

Correct Answer

(D) 0.557, 0.418

Step-by-step Solution

Detailed explanation

\(\begin{array}{ccc} A & \rightleftharpoons & B \\ 0.5 M & & 0.375 M \end{array} \quad\) (At equilibrium) \(K_{eq} = \frac{[B]_{eq}}{[A]_{eq}} = \frac{0.375}{0.5} = 0.75\) Now 0.1 mole of A is added so reaction will move in forward direction. \(A \rightleftharpoons B\)…