JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
In a closed flask at \(600\) K, one mole of X\(_2\)Y\(_4\)(g) attains equilibrium as given below :
\(\text{X}_2\text{Y}_4(g) \rightleftharpoons 2\text{XY}_2(g)\)
At equilibrium, \(75\%\) X\(_2\)Y\(_4\)(g) was dissociated and the total pressure is \(1\) atm. The magnitude of \(\Delta_r G^{\ominus}\) (in kJ mol\(^{-1}\)) at this temperature is __________. (Nearest Integer) (Given : R \(= 8.3\) J mol\(^{-1}\) K\(^{-1}\); \(\ln 10 = 2.3\), \(\log 2 = 0.3\), \(\log 3 = 0.48\), \(\log 5 = 0.69\), \(\log 7 = 0.84\))
- A 8
- B 10
- C 12
- D 14
Answer & Solution
Correct Answer
(A) 8
Step-by-step Solution
Detailed explanation
The given equilibrium reaction is: \(\text{X}_2\text{Y}_4(g) \rightleftharpoons 2\text{XY}_2(g)\) Initial moles: \(1\) Degree of dissociation, \(\alpha = 0.75\) Moles of \(\text{X}_2\text{Y}_4\) at equilibrium \(= 1 - \alpha = 1 - 0.75 = 0.25\) Moles of \(\text{XY}_2\) at…
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