JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The density of \(\mathrm{NaOH}\) solution is \(1.2 \mathrm{gcm}^{-3} .\) The molality of this solution is \(....\,m\) (Round off to the NearestInteger) [Use:Atomicmasses:\(Na:23.0\,u \mathrm{O}: 16.0 \,\mathrm{u} \quad \mathrm{H}: 1.0 \,\mathrm{u}\), Density of \(\mathrm{H}_{2} \mathrm{O}: 1.0 \,\mathrm{~g} \,\mathrm{~cm}^{-3}\) ]
- A \(6\)
- B \(5\)
- C \(4\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
Consider \(1\, \ell\) solution mass of solution \(=(1.2 \times 1000)\, \mathrm{g}\) \(=1200\, \mathrm{gm}\) Neglecting volume of \(\mathrm{NaOH}\) Mass of water \(=1000\, \mathrm{gm}\) \(\Rightarrow\) Mass of \(\mathrm{NaOH}=(1200-1000)\, \mathrm{gm}\) \(=200\, \mathrm{gm}\)…
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