JEE Mains · Chemistry · STD 11 - 2. structure of atom
The wavelength of electrons accelerated from rest through a potential difference of \(40\, \mathrm{kV}\) is \(\mathrm{X}\, \times\) \(10^{-12} \,\mathrm{~m}\). The value of \(\mathrm{x}\) is \(......\). (Nearest integer) Given : Mass of electrons \(=9.1 \times 10^{-31}\, \mathrm{~kg}\) Charge on an electron \(=1.6 \times 10^{-19}\, \mathrm{C}\) Planck's constant \(=6.63 \times 10^{-34\,} \mathrm{Js}\)
- A \(9\)
- B \(4\)
- C \(5\)
- D \(6\)
Answer & Solution
Correct Answer
(D) \(6\)
Step-by-step Solution
Detailed explanation
De-broglie-wave length of electron: \(\lambda_{c}=\frac{h}{\sqrt{2 m(\mathrm{KE})}}\) \(\because \mathrm{e}^{-}\,{\text {is accelerated }}{\text { from rest }}{\Rightarrow \mathrm{KE}=\mathrm{q} \times \mathrm{V}}\) \(\lambda=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mqv}}}\)…
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