JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
At \(363\,K ,\) the vapour pressure of \(A\) is \(21 \,kPa\) and that of \(B\) is \(18\, kPa\). One mole of \(A\) and \(2\) moles of \(B\) are mixed. Assuming that this solution is ideal, the vapour pressure of the mixture is ....... \(kPa\). (Round of to the Nearest Integer).
- A \(19\)
- B \(21\)
- C \(25\)
- D \(36\)
Answer & Solution
Correct Answer
(A) \(19\)
Step-by-step Solution
Detailed explanation
Given \(P _{ A }^{0}=21\, kPa \quad \Rightarrow P _{ B }^{0}=18\, kPa\) \(\rightarrow\) An Ideal solution is prepared by mixing \(1\, mol\) \(A\) and \(2 \,mol\, B\). \(\rightarrow X_{A}=\frac{1}{3}\) and \(X_{B}=\frac{2}{3}\) \(\rightarrow\) Acc to Raoult's low…
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