JEE Mains · Chemistry · STD 11 - 2. structure of atom
An accelerated electron has a speed of \(5 \times 10^{6} \,\mathrm{~ms}^{-1}\) with an uncertainty of \(0.02\,\%\). The uncertainty in finding its location while in motion is \(x \times 10^{-9}\, \mathrm{~m}\). The value of \(x\) is \(......\) (Nearest integer) [Use mass of electron \(\left.=9.1 \times 10^{-31}\, \mathrm{~kg}, \mathrm{~h}=6.63 \times 10^{-34}\, \mathrm{~J} \mathrm{~s}, \)\(\pi=3.14\right]\)
- A \(12\)
- B \(36\)
- C \(58\)
- D \(72\)
Answer & Solution
Correct Answer
(C) \(58\)
Step-by-step Solution
Detailed explanation
\(\Delta v=\frac{0.02}{100} \times 5 \times 10^{6}=10^{3} \,\mathrm{~m} / \mathrm{s}\) According to Heisenberg uncertainty principle \(\Delta \mathrm{X} \cdot \Delta \mathrm{v}=\frac{\mathrm{h}}{4 \pi \,\mathrm{m}}\)…
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