JEE Mains · Physics · STD 12 - 3. current electricity
A resistor dissipates \(192\, {J}\) of energy in \(1\, {s}\) when a current of \(4\, {A}\) is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in \(5 \,{s}\) in \(.....\,J.\)
- A \(8125\)
- B \(38400\)
- C \(384\)
- D \(3840\)
Answer & Solution
Correct Answer
(D) \(3840\)
Step-by-step Solution
Detailed explanation
\({E}={i}^{2} {Rt}\) \(192=16({R})(1)\) \({R}=12\, \Omega\) \({E}^{1}=(8)^{2}(12)(5)\) \(=3840\, {J}\)
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