JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K \(MX ( s ) \rightleftharpoons M ^{+}( aq )+ X ^{-}( aq ) ; K _{ sp }=10^{-10}\) If the standard reduction potential for \(M ^{+}( aq ) \xrightarrow{+ e ^{-}} M ( s )\) is \(\left( E _{ M ^{+} / M }^{\ominus}\right)=0.79 V\), then the value of the standard reduction potential for the metal/metal insoluble salt electrode \(E _{ X ^{-} / MX ( s ) / M }^{\ominus}\) is __________ mV. (nearest integer) [Given: \(\frac{2.303 R T}{F}=0.059 V\) ]
- A 200
- B 790
- C 590
- D 1380
Answer & Solution
Correct Answer
(A) 200
Step-by-step Solution
Detailed explanation
\(E _{ X ^{-} / MX ( s ) / M }^{ o }= E _{ M ^{+} / M }^{ o }+\frac{0.0591}{ n } \log K _{ sp }\) \(=0.79+\frac{0.059}{1} \log 10^{-10}\) \(=0.79-0.59\) \(=0.20 V=200 mV\)
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