JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
If \(K_{sp}\) of \(Ag_2CO_3\) is \(8 \times10^{-12},\) the molar solubility of \(Ag_2CO_3\) in \(0.1\,M\,AgNO_3\) is
- A \(8\times 10^{-12}\,M\)
- B \(8\times 10^{-11}\,M\)
- C \(8\times 10^{-10}\,M\)
- D \(8\times 10^{-13}\,M\)
Answer & Solution
Correct Answer
(C) \(8\times 10^{-10}\,M\)
Step-by-step Solution
Detailed explanation
\(8 \times {10^{ - 12}} = {(2S' + 0.1)^2}S'\) Or \(S' = 8\times 10^{-10}\,M\)
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