- JEE Mains 2021
- Hard
- MCQ
The fractional change in the magnetic field intensity at a distance \('r'\) from centre on the axis of current carrying coil of radius \('a'\) to the magnetic field intensity at the centre of the same coil is : (Take \(r << a )\)
Answer & Solution
(D) \(\frac{3}{2} \frac{ r ^{2}}{ a ^{2}}\)
Step-by-step Solution
Detailed explanation
\(B _{\text {centre }}=\frac{\mu_{0} i }{2 R }\)
\(\therefore B _{\text {centre }}=\frac{\mu_{0} i }{2 a }\)
\(\therefore B _{ axis }=\frac{\mu_{0} ia ^{2}}{2\left( a ^{2}+ r ^{2}\right)^{3 / 2}}\)
\(\therefore\) fractional change in magnetic field \(=\)
\(\frac{\frac{\mu_{0} i }{2 a }-\frac{\mu_{0} ia ^{2}}{2\left( a ^{2}+ r ^{2}\right)^{3 / 2}}}{{\frac{\mu_{0} i }{2 a }}}=1-\frac{1}{\left[1+\left(\frac{ r ^{2}}{ a ^{2}}\right)\right]^{3 / 2}}\)
\(\approx 1-\left[1-\frac{3}{2} \frac{ r ^{2}}{ a ^{2}}\right]=\frac{3}{2} \frac{ r ^{2}}{ a ^{2}}\)
Note : \(\left(1+\frac{ r ^{2}}{ a ^{2}}\right)^{-3 / 2} \approx\left(1-\frac{3}{2} \frac{ r ^{2}}{ a ^{2}}\right)\)
[True only if \(r << a ]\)
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