JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
If solubility product of \(Z{r_3}{\left( {P{O_4}} \right)_4}\) is denoted by \(K_{SP}\) and its molar solubility is denoted by \(S\), then which of the following relation between \(S\) and \(K_{SP}\) is correct?
- A \(S = {\left( {\frac{{{K_{SP}}}}{{6912}}} \right)^{1/7}}\)
- B \(S = {\left( {\frac{{{K_{SP}}}}{{144}}} \right)^{1/6}}\)
- C \(S = {\left( {\frac{{{K_{SP}}}}{{929}}} \right)^{1/9}}\)
- D \(S = {\left( {\frac{{{K_{SP}}}}{{216}}} \right)^{1/7}}\)
Answer & Solution
Correct Answer
(A) \(S = {\left( {\frac{{{K_{SP}}}}{{6912}}} \right)^{1/7}}\)
Step-by-step Solution
Detailed explanation
\(Z{r_4}{(P{O_4})_4}(s) \rightleftharpoons \mathop {3Z{r^{4 + }}(aq.)}\limits_{3S\,M} + \mathop {4PO_4^{3 - }(aq.)}\limits_{4S\,M} \) \({K_{sp}} = {[Z{r^{4 + }}]^3}{[P{O_4}^{3 - }]^4} = {(3S)^3}.{(4S)^4} = 6912\,{S^7}\)…
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