JEE Mains · Chemistry · STD 12 - 5. Co-ordination chemistry
Consider a mixture 'X' which is made by dissolving 0.4 mol of \( [Co(NH_{3})_{5}SO_{4}]Br \) and 0.4 mol of \( [Co(NH_{3})_{5}Br]SO_{4} \) in water to make 4 L of solution. When 2 L of mixture 'X' is allowed to react with excess of \( AgNO_{3} \), it forms precipitate 'Y'. The rest 2 L of mixture 'X' reacts with excess \( BaCl_{2} \) to form precipitate 'Z'. Which of the following statements is CORRECT.
- A 0.2 mol of 'Z' is formed
- B Y' is \( BaSO_{4} \) and 'Z' is AgBr
- C 0.4 mol of 'Z' is formed
- D 0.1 mol of 'Y' is formed
Answer & Solution
Correct Answer
(A) 0.2 mol of 'Z' is formed
Step-by-step Solution
Detailed explanation
0.4 mol \( [Co(NH_{3})_{5}SO_{4}]Br \) + 0.4 mol \( [Co(NH_{3})_{5}Br]SO_{4} \) are present in 4 lit. solution. 2 lit. of mixture will contain 0.2 mol of each complex. 2 lit. mixture on reaction with excess \( AgNO_{3} \), 0.2 mole AgBr will be formed (Y). 2 lit. mixture on…
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