In nucleuphilic substitution reaction, order of halogens as incoming (attacking) nucleophile is:
\(I^-> Br^ - > Cl^-\)
The order of halogens as departing nucleophile should be

A \(Br^- > I^->Cl^-\)
B \({I^ - } > B{r^ - } > C{l^{^ - }}\)
C \(C{l^{^ - }} > B{r^ - } > {I^ - }\)
D \(C{l^{^ - }} > {I^ - } > B{r^ - }\)

Verified Solution

Answer & Solution

Correct Answer

(B) \({I^ - } > B{r^ - } > C{l^{^ - }}\)

Step-by-step Solution

Detailed explanation

Since the leaving group breaks away as a base, it is easier to displace weaker bases as compared to stronger bases. Thus less basic the substituent. the more easily it is displaced. Since the basic strength of the given groups is in order. \({I^ - } < B{r^ - } < Cl^-\) Thus the…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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In nucleuphilic substitution reaction, order of halogens as incoming (attacking) nucleophile is: \(I^-> Br^ - > Cl^-\) The order of halogens as departing nucleophile should be

Step-by-step Solution

In nucleuphilic substitution reaction, order of halogens as incoming (attacking) nucleophile is:
\(I^-> Br^ - > Cl^-\)
The order of halogens as departing nucleophile should be