JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
Given \(E^o_{Cl_2/Cl^-} = 1.36\,V,\) \(E^o_{Cr^{3+}/Cr}= -0.74\,V,\) \(E^o_{Cr_2/O_7^{2-}/Cr^{3+}}=1.33\,V,\) \(E^o_{MnO^-_4/Mn^{2+}} = 1.51\,V\) Among the following, the strongest reducing agent is
- A \(Cr\)
- B \(Mn^{2+}\)
- C \(Cr^{+3}\)
- D \(Cl^-\)
Answer & Solution
Correct Answer
(A) \(Cr\)
Step-by-step Solution
Detailed explanation
Lower the reduction potential, greater is the tendency of the element to get oxidized, hence, greater is the reducing ability. Since, chromium system has lowest reduction potential; therefore, it is the strongest reducing agent.
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