JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Moment of inertia about an axis \(AB\) for a rod of mass \(40\) kg and length \(3\) m is same as that of a solid sphere of mass of \(10\) kg and radius \(R\) about an axis parallel to \(AB\) axis with separation of \(3\) m as shown in figure below. The value of \(R\) is given as \(\sqrt{\dfrac{\alpha}{2}}\). The value of \(\alpha\) is _______.
- A 10
- B 15
- C 20
- D 25
Answer & Solution
Correct Answer
(B) 15
Step-by-step Solution
Detailed explanation
Moment of inertia of the rod about axis \(AB\) passing through one of its ends: \(I_{\text{rod}} = \dfrac{ML^2}{3} = \dfrac{40 \times (3)^2}{3} = \dfrac{40 \times 9}{3} = 120\text{ kg}\cdot\text{m}^2\) Moment of inertia of the solid sphere about the same axis \(AB\), using the…
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